Optimal. Leaf size=45 \[ \frac{x^{m+4} (a B+A b)}{m+4}+\frac{a A x^{m+1}}{m+1}+\frac{b B x^{m+7}}{m+7} \]
[Out]
_______________________________________________________________________________________
Rubi [A] time = 0.0703345, antiderivative size = 45, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 1, integrand size = 18, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.056 \[ \frac{x^{m+4} (a B+A b)}{m+4}+\frac{a A x^{m+1}}{m+1}+\frac{b B x^{m+7}}{m+7} \]
Antiderivative was successfully verified.
[In] Int[x^m*(a + b*x^3)*(A + B*x^3),x]
[Out]
_______________________________________________________________________________________
Rubi in Sympy [A] time = 8.51197, size = 37, normalized size = 0.82 \[ \frac{A a x^{m + 1}}{m + 1} + \frac{B b x^{m + 7}}{m + 7} + \frac{x^{m + 4} \left (A b + B a\right )}{m + 4} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**m*(b*x**3+a)*(B*x**3+A),x)
[Out]
_______________________________________________________________________________________
Mathematica [A] time = 0.0478, size = 41, normalized size = 0.91 \[ x^m \left (\frac{x^4 (a B+A b)}{m+4}+\frac{a A x}{m+1}+\frac{b B x^7}{m+7}\right ) \]
Antiderivative was successfully verified.
[In] Integrate[x^m*(a + b*x^3)*(A + B*x^3),x]
[Out]
_______________________________________________________________________________________
Maple [B] time = 0.006, size = 110, normalized size = 2.4 \[{\frac{{x}^{1+m} \left ( Bb{m}^{2}{x}^{6}+5\,Bbm{x}^{6}+4\,bB{x}^{6}+Ab{m}^{2}{x}^{3}+Ba{m}^{2}{x}^{3}+8\,Abm{x}^{3}+8\,Bam{x}^{3}+7\,A{x}^{3}b+7\,B{x}^{3}a+Aa{m}^{2}+11\,Aam+28\,Aa \right ) }{ \left ( 7+m \right ) \left ( 4+m \right ) \left ( 1+m \right ) }} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^m*(b*x^3+a)*(B*x^3+A),x)
[Out]
_______________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^3 + A)*(b*x^3 + a)*x^m,x, algorithm="maxima")
[Out]
_______________________________________________________________________________________
Fricas [A] time = 0.246423, size = 124, normalized size = 2.76 \[ \frac{{\left ({\left (B b m^{2} + 5 \, B b m + 4 \, B b\right )} x^{7} +{\left ({\left (B a + A b\right )} m^{2} + 7 \, B a + 7 \, A b + 8 \,{\left (B a + A b\right )} m\right )} x^{4} +{\left (A a m^{2} + 11 \, A a m + 28 \, A a\right )} x\right )} x^{m}}{m^{3} + 12 \, m^{2} + 39 \, m + 28} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^3 + A)*(b*x^3 + a)*x^m,x, algorithm="fricas")
[Out]
_______________________________________________________________________________________
Sympy [A] time = 4.45935, size = 410, normalized size = 9.11 \[ \begin{cases} - \frac{A a}{6 x^{6}} - \frac{A b}{3 x^{3}} - \frac{B a}{3 x^{3}} + B b \log{\left (x \right )} & \text{for}\: m = -7 \\- \frac{A a}{3 x^{3}} + A b \log{\left (x \right )} + B a \log{\left (x \right )} + \frac{B b x^{3}}{3} & \text{for}\: m = -4 \\A a \log{\left (x \right )} + \frac{A b x^{3}}{3} + \frac{B a x^{3}}{3} + \frac{B b x^{6}}{6} & \text{for}\: m = -1 \\\frac{A a m^{2} x x^{m}}{m^{3} + 12 m^{2} + 39 m + 28} + \frac{11 A a m x x^{m}}{m^{3} + 12 m^{2} + 39 m + 28} + \frac{28 A a x x^{m}}{m^{3} + 12 m^{2} + 39 m + 28} + \frac{A b m^{2} x^{4} x^{m}}{m^{3} + 12 m^{2} + 39 m + 28} + \frac{8 A b m x^{4} x^{m}}{m^{3} + 12 m^{2} + 39 m + 28} + \frac{7 A b x^{4} x^{m}}{m^{3} + 12 m^{2} + 39 m + 28} + \frac{B a m^{2} x^{4} x^{m}}{m^{3} + 12 m^{2} + 39 m + 28} + \frac{8 B a m x^{4} x^{m}}{m^{3} + 12 m^{2} + 39 m + 28} + \frac{7 B a x^{4} x^{m}}{m^{3} + 12 m^{2} + 39 m + 28} + \frac{B b m^{2} x^{7} x^{m}}{m^{3} + 12 m^{2} + 39 m + 28} + \frac{5 B b m x^{7} x^{m}}{m^{3} + 12 m^{2} + 39 m + 28} + \frac{4 B b x^{7} x^{m}}{m^{3} + 12 m^{2} + 39 m + 28} & \text{otherwise} \end{cases} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**m*(b*x**3+a)*(B*x**3+A),x)
[Out]
_______________________________________________________________________________________
GIAC/XCAS [A] time = 0.216468, size = 225, normalized size = 5. \[ \frac{B b m^{2} x^{7} e^{\left (m{\rm ln}\left (x\right )\right )} + 5 \, B b m x^{7} e^{\left (m{\rm ln}\left (x\right )\right )} + 4 \, B b x^{7} e^{\left (m{\rm ln}\left (x\right )\right )} + B a m^{2} x^{4} e^{\left (m{\rm ln}\left (x\right )\right )} + A b m^{2} x^{4} e^{\left (m{\rm ln}\left (x\right )\right )} + 8 \, B a m x^{4} e^{\left (m{\rm ln}\left (x\right )\right )} + 8 \, A b m x^{4} e^{\left (m{\rm ln}\left (x\right )\right )} + 7 \, B a x^{4} e^{\left (m{\rm ln}\left (x\right )\right )} + 7 \, A b x^{4} e^{\left (m{\rm ln}\left (x\right )\right )} + A a m^{2} x e^{\left (m{\rm ln}\left (x\right )\right )} + 11 \, A a m x e^{\left (m{\rm ln}\left (x\right )\right )} + 28 \, A a x e^{\left (m{\rm ln}\left (x\right )\right )}}{m^{3} + 12 \, m^{2} + 39 \, m + 28} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((B*x^3 + A)*(b*x^3 + a)*x^m,x, algorithm="giac")
[Out]